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(F)=(F+8)(F-11)
We move all terms to the left:
(F)-((F+8)(F-11))=0
We multiply parentheses ..
-((+F^2-11F+8F-88))+F=0
We calculate terms in parentheses: -((+F^2-11F+8F-88)), so:We add all the numbers together, and all the variables
(+F^2-11F+8F-88)
We get rid of parentheses
F^2-11F+8F-88
We add all the numbers together, and all the variables
F^2-3F-88
Back to the equation:
-(F^2-3F-88)
F-(F^2-3F-88)=0
We get rid of parentheses
-F^2+F+3F+88=0
We add all the numbers together, and all the variables
-1F^2+4F+88=0
a = -1; b = 4; c = +88;
Δ = b2-4ac
Δ = 42-4·(-1)·88
Δ = 368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{368}=\sqrt{16*23}=\sqrt{16}*\sqrt{23}=4\sqrt{23}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{23}}{2*-1}=\frac{-4-4\sqrt{23}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{23}}{2*-1}=\frac{-4+4\sqrt{23}}{-2} $
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