F(x)=(x+12)(x+11)

Solution for F(x)=(x+12)(x+11) equation:

(F)=(F+12)(F+11)

We move all terms to the left:

(F)-((F+12)(F+11))=0

We multiply parentheses ..

-((+F^2+11F+12F+132))+F=0


We calculate terms in parentheses: -((+F^2+11F+12F+132)), so:

(+F^2+11F+12F+132)

We get rid of parentheses

F^2+11F+12F+132

We add all the numbers together, and all the variables

F^2+23F+132

Back to the equation:

-(F^2+23F+132)


We add all the numbers together, and all the variables

F-(F^2+23F+132)=0

We get rid of parentheses

-F^2+F-23F-132=0

We add all the numbers together, and all the variables

-1F^2-22F-132=0

a = -1; b = -22; c = -132;
Δ = b2-4ac
Δ = -222-4·(-1)·(-132)
Δ = -44
Delta is less than zero, so there is no solution for the equation