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(F)=(5F+30)/F
We move all terms to the left:
(F)-((5F+30)/F)=0
Domain of the equation: F)!=0We multiply all the terms by the denominator
F!=0/1
F!=0
F∈R
F*F)-((5F+30)=0
Wy multiply elements
F^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$F=\frac{-b}{2a}=\frac{0}{2}=0$
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