F(x)=(2/5)x

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Solution for F(x)=(2/5)x equation: 



(F)=(2/5)F

We move all terms to the left:

(F)-((2/5)F)=0



Domain of the equation: 5)F)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

F-((+2/5)F)=0

We multiply all the terms by the denominator


F*5)F)-((+2=0

Wy multiply elements

5F^2+2=0

a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation

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