F(t)=-2t2+3t-6

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Solution for F(t)=-2t2+3t-6 equation: 



(F)=-2F^2+3F-6

We move all terms to the left:

(F)-(-2F^2+3F-6)=0

We get rid of parentheses

2F^2-3F+F+6=0

We add all the numbers together, and all the variables

2F^2-2F+6=0

a = 2; b = -2; c = +6;
Δ = b2-4ac
Δ = -22-4·2·6
Δ = -44
Delta is less than zero, so there is no solution for the equation

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