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(F)=50-5(F-1)
We move all terms to the left:
(F)-(50-5(F-1))=0
We calculate terms in parentheses: -(50-5(F-1)), so:We get rid of parentheses
50-5(F-1)
determiningTheFunctionDomain -5(F-1)+50
We multiply parentheses
-5F+5+50
We add all the numbers together, and all the variables
-5F+55
Back to the equation:
-(-5F+55)
F+5F-55=0
We add all the numbers together, and all the variables
6F-55=0
We move all terms containing F to the left, all other terms to the right
6F=55
F=55/6
F=9+1/6
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