F(n)=5(n-1)+8

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Solution for F(n)=5(n-1)+8 equation: 



(F)=5(F-1)+8

We move all terms to the left:

(F)-(5(F-1)+8)=0



We calculate terms in parentheses: -(5(F-1)+8), so:

5(F-1)+8

We multiply parentheses

5F-5+8

We add all the numbers together, and all the variables

5F+3

Back to the equation:

-(5F+3)



We get rid of parentheses

F-5F-3=0

We add all the numbers together, and all the variables

-4F-3=0

We move all terms containing F to the left, all other terms to the right

-4F=3

F=3/-4

F=-3/4

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