F(n)=24(1/2)(n-1)

Solution for F(n)=24(1/2)(n-1) equation:

(F)=24(1/2)(F-1)

We move all terms to the left:

(F)-(24(1/2)(F-1))=0


Domain of the equation: 2)(F-1))!=0

F∈R


We add all the numbers together, and all the variables

F-(24(+1/2)(F-1))=0

We multiply parentheses ..

-(24(+F^2+1/2*-1))+F=0

We multiply all the terms by the denominator


-(24(+F^2+1+F*2*-1))=0


We calculate terms in parentheses: -(24(+F^2+1+F*2*-1)), so:

24(+F^2+1+F*2*-1)

We multiply parentheses

24F^2+48F^2+24-24

We add all the numbers together, and all the variables

72F^2

Back to the equation:

-(72F^2)


a = -72; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-72)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{-144}=0$