F(n)=2(n+2)

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Solution for F(n)=2(n+2) equation: 



(F)=2(F+2)

We move all terms to the left:

(F)-(2(F+2))=0



We calculate terms in parentheses: -(2(F+2)), so:

2(F+2)

We multiply parentheses

2F+4

Back to the equation:

-(2F+4)



We get rid of parentheses

F-2F-4=0

We add all the numbers together, and all the variables

-1F-4=0

We move all terms containing F to the left, all other terms to the right

-F=4

F=4/-1

F=-4

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