F(d)=110+.12d

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Solution for F(d)=110+.12d equation: 



(F)=110+.12F

We move all terms to the left:

(F)-(110+.12F)=0

We add all the numbers together, and all the variables

F-(.12F+110)=0

We get rid of parentheses

F-.12F-110=0

We add all the numbers together, and all the variables

0.88F-110=0

We move all terms containing F to the left, all other terms to the right

0.88F=110

F=110/0.88

F=125

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