F(3)=4x2+6

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Solution for F(3)=4x2+6 equation: 



(3)=4F^2+6

We move all terms to the left:

(3)-(4F^2+6)=0

We get rid of parentheses

-4F^2-6+3=0

We add all the numbers together, and all the variables

-4F^2-3=0

a = -4; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-4)·(-3)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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