F(3)=4/5x-2

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Solution for F(3)=4/5x-2 equation: 



(3)=4/5F-2

We move all terms to the left:

(3)-(4/5F-2)=0



Domain of the equation: 5F-2)!=0

F∈R



We get rid of parentheses

-4/5F+2+3=0

We multiply all the terms by the denominator


2*5F+3*5F-4=0

Wy multiply elements

10F+15F-4=0

We add all the numbers together, and all the variables

25F-4=0

We move all terms containing F to the left, all other terms to the right

25F=4

F=4/25

F=4/25

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