F(10)=300+35x

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Solution for F(10)=300+35x equation: 



(10)=300+35F

We move all terms to the left:

(10)-(300+35F)=0

We add all the numbers together, and all the variables

-(35F+300)+10=0

We get rid of parentheses

-35F-300+10=0

We add all the numbers together, and all the variables

-35F-290=0

We move all terms containing F to the left, all other terms to the right

-35F=290

F=290/-35

F=-8+2/7

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