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(-5)=2/5F+3
We move all terms to the left:
(-5)-(2/5F+3)=0
Domain of the equation: 5F+3)!=0We add all the numbers together, and all the variables
F∈R
-(2/5F+3)-5=0
We get rid of parentheses
-2/5F-3-5=0
We multiply all the terms by the denominator
-3*5F-5*5F-2=0
Wy multiply elements
-15F-25F-2=0
We add all the numbers together, and all the variables
-40F-2=0
We move all terms containing F to the left, all other terms to the right
-40F=2
F=2/-40
F=-1/20
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