F(-2)=4x-3+10

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Solution for F(-2)=4x-3+10 equation: 



(-2)=4F-3+10

We move all terms to the left:

(-2)-(4F-3+10)=0

We add all the numbers together, and all the variables

-(4F+7)+(-2)=0

We add all the numbers together, and all the variables

-(4F+7)-2=0

We get rid of parentheses

-4F-7-2=0

We add all the numbers together, and all the variables

-4F-9=0

We move all terms containing F to the left, all other terms to the right

-4F=9

F=9/-4

F=-2+1/4

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