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(x+3)^2+(x+3)^3+x+3 = 0
2^x-cos(4*x)
(4*x-8)/3 = 8
-10 = (-1/2)*w
x+3;(x+1)(x-3);4x+4;x+2
| 6d+4+34= | | -(x-1)=10 | | b^2-32b=0 | | (2x+5)(1-x)=0 | | -3=m-m | | -3.5x+2+5x+10=0 | | (11x-37)+(5x-59)=54 | | 2-3[6(5y-6)]= | | 9d^2*5= | | 3z+15=2(2z-8) | | 19+ln(5x)=ln(16) | | 2w-6w+7=11-5w | | 10x-15=9x-15 | | Y+4x=-5 | | -4n+15=n-8(b+2n) | | (4x-8)/3=8 | | -6r+8=40 | | 40+.45(m)=70+.35(g) | | 8x^7+28x^6+20x^5= | | 2a+3a-13=a+3 | | 40+.45(m)=70+.35(m) | | X-25+x-75=275 | | -10=-1/2w | | -3.5x=7 | | 0.723600*1000= | | 11(z+2)-4(z-4)=4(z-1)+2(z-4) | | 4+3(T+4)=5(3t-10) | | -9n+6=-28+3n | | ax+5a=a^2 | | (x-3i)(x-3i)=34 | | -34+z=13 | | 3t^2-8t-36=0 |