D-2(x+3)-3(x-1)=-4(x-5)

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Solution for D-2(x+3)-3(x-1)=-4(x-5) equation: 



-2(D+3)-3(D-1)=-4(D-5)

We move all terms to the left:

-2(D+3)-3(D-1)-(-4(D-5))=0

We multiply parentheses

-2D-3D-(-4(D-5))-6+3=0



We calculate terms in parentheses: -(-4(D-5)), so:

-4(D-5)

We multiply parentheses

-4D+20

Back to the equation:

-(-4D+20)



We add all the numbers together, and all the variables

-5D-(-4D+20)-3=0

We get rid of parentheses

-5D+4D-20-3=0

We add all the numbers together, and all the variables

-1D-23=0

We move all terms containing D to the left, all other terms to the right

-D=23

D=23/-1

D=-23

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