D(y-5)=2(10+3y)

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Solution for D(y-5)=2(10+3y) equation: 



(D-5)=2(10+3D)

We move all terms to the left:

(D-5)-(2(10+3D))=0

We add all the numbers together, and all the variables

(D-5)-(2(3D+10))=0

We get rid of parentheses

D-(2(3D+10))-5=0



We calculate terms in parentheses: -(2(3D+10)), so:

2(3D+10)

We multiply parentheses

6D+20

Back to the equation:

-(6D+20)



We get rid of parentheses

D-6D-20-5=0

We add all the numbers together, and all the variables

-5D-25=0

We move all terms containing D to the left, all other terms to the right

-5D=25

D=25/-5

D=-5

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