Cos(4x)+sin(2x)=0

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Solution for Cos(4x)+sin(2x)=0 equation:


Simplifying
Cos(4x) + sin(2x) = 0

Remove parenthesis around (4x)
osC * 4x + sin(2x) = 0

Reorder the terms for easier multiplication:
4osC * x + sin(2x) = 0

Multiply osC * x
4osxC + sin(2x) = 0

Remove parenthesis around (2x)
4osxC + ins * 2x = 0

Reorder the terms for easier multiplication:
4osxC + 2ins * x = 0

Multiply ins * x
4osxC + 2insx = 0

Reorder the terms:
2insx + 4osxC = 0

Solving
2insx + 4osxC = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4osxC' to each side of the equation.
2insx + 4osxC + -4osxC = 0 + -4osxC

Combine like terms: 4osxC + -4osxC = 0
2insx + 0 = 0 + -4osxC
2insx = 0 + -4osxC
Remove the zero:
2insx = -4osxC

Divide each side by '2nsx'.
i = -2n-1oC

Simplifying
i = -2n-1oC

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