Cos(2x)+7cosx+4=0

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Solution for Cos(2x)+7cosx+4=0 equation: 


Simplifying
Cos(2x) + 7cosx + 4 = 0

Remove parenthesis around (2x)
osC * 2x + 7cosx + 4 = 0

Reorder the terms for easier multiplication:
2osC * x + 7cosx + 4 = 0

Multiply osC * x
2osxC + 7cosx + 4 = 0

Reorder the terms:
4 + 7cosx + 2osxC = 0

Solving
4 + 7cosx + 2osxC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 7cosx + -4 + 2osxC = 0 + -4

Reorder the terms:
4 + -4 + 7cosx + 2osxC = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 7cosx + 2osxC = 0 + -4
7cosx + 2osxC = 0 + -4

Combine like terms: 0 + -4 = -4
7cosx + 2osxC = -4

Add '-2osxC' to each side of the equation.
7cosx + 2osxC + -2osxC = -4 + -2osxC

Combine like terms: 2osxC + -2osxC = 0
7cosx + 0 = -4 + -2osxC
7cosx = -4 + -2osxC

Divide each side by '7osx'.
c = -0.5714285714o-1s-1x-1 + -0.2857142857C

Simplifying
c = -0.5714285714o-1s-1x-1 + -0.2857142857C

Reorder the terms:
c = -0.2857142857C + -0.5714285714o-1s-1x-1

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