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=C2+8C+16
We move all terms to the left:
-(C2+8C+16)=0
We add all the numbers together, and all the variables
-(+C^2+8C+16)=0
We get rid of parentheses
-C^2-8C-16=0
We add all the numbers together, and all the variables
-1C^2-8C-16=0
a = -1; b = -8; c = -16;
Δ = b2-4ac
Δ = -82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$C=\frac{-b}{2a}=\frac{8}{-2}=-4$
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