C=9/5(k-28)

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Solution for C=9/5(k-28) equation: 



=9/5(C-28)

We move all terms to the left:

-(9/5(C-28))=0



Domain of the equation: 5(C-28))!=0

C∈R



We multiply all the terms by the denominator


-(9=0

We add all the numbers together, and all the variables

=0

C=0/1

C=0

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