C=5/9(-40c-32)

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Solution for C=5/9(-40c-32) equation: 



=5/9(-40C-32)

We move all terms to the left:

-(5/9(-40C-32))=0



Domain of the equation: 9(-40C-32))!=0

C∈R



We multiply all the terms by the denominator


-(5=0

We add all the numbers together, and all the variables

=0

C=0/1

C=0

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