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=2C/C+12C
We move all terms to the left:
-(2C/C+12C)=0
Domain of the equation: C+12C)!=0We add all the numbers together, and all the variables
C∈R
-(+12C+2C/C)=0
We get rid of parentheses
-12C-2C/C=0
We multiply all the terms by the denominator
-12C*C-2C=0
We add all the numbers together, and all the variables
-2C-12C*C=0
Wy multiply elements
-12C^2-2C=0
a = -12; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-12)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-12}=\frac{0}{-24} =0 $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-12}=\frac{4}{-24} =-1/6 $
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