C=28+3s.M=10s

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Solution for C=28+3s.M=10s equation: 



=28+3C.=10C

We move all terms to the left:

-(28+3C.)=0

We add all the numbers together, and all the variables

-(3C.+28)=0

We get rid of parentheses

-3C.-28=0

We move all terms containing C to the left, all other terms to the right

-3C.=28

C=28/1

C=28

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