C=(4+k)

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Solution for C=(4+k) equation: 



=(4+C)

We move all terms to the left:

-((4+C))=0

We add all the numbers together, and all the variables

-((C+4))=0



We calculate terms in parentheses: -((C+4)), so:

(C+4)

We get rid of parentheses

C+4

Back to the equation:

-(C+4)



We get rid of parentheses

-C-4=0

We add all the numbers together, and all the variables

-1C-4=0

We move all terms containing C to the left, all other terms to the right

-C=4

C=4/-1

C=-4

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