C2+7c+12=(c+)

Solution for C2+7c+12=(c+) equation:

2+7C+12=(C+)

We move all terms to the left:

2+7C+12-((C+))=0

We add all the numbers together, and all the variables

7C-((+C))+2+12=0

We add all the numbers together, and all the variables

7C-((+C))+14=0


We calculate terms in parentheses: -((+C)), so:

(+C)

We get rid of parentheses

C

Back to the equation:

-(C)


We add all the numbers together, and all the variables

6C+14=0

We move all terms containing C to the left, all other terms to the right

6C=-14

C=-14/6

C=-2+1/3