C/3c=27

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Solution for C/3c=27 equation: 



/3C=27

We move all terms to the left:

/3C-(27)=0



Domain of the equation: 3C!=0

C!=0/3

C!=0

C∈R



We multiply all the terms by the denominator


-27*3C+=0

We add all the numbers together, and all the variables

-27*3C=0

Wy multiply elements

-81C=0

C=0/-81

C=0

Równanie nie ma rozwiązania

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