C/(2c+2)c=5

Solution for C/(2c+2)c=5 equation:

/(2C+2)C=5

We move all terms to the left:

/(2C+2)C-(5)=0


Domain of the equation: (2C+2)C!=0

C∈R


We multiply all the terms by the denominator


-5*(2C+2)C+=0

We add all the numbers together, and all the variables

-5*(2C+2)C=0

We multiply parentheses

-10C^2-10C=0

a = -10; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-10)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-10}=\frac{0}{-20}
=0
$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-10}=\frac{20}{-20}
=-1
$