C+5c+4=3(2c-1)

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Solution for C+5c+4=3(2c-1) equation:


Simplifying
C + 5c + 4 = 3(2c + -1)

Reorder the terms:
4 + C + 5c = 3(2c + -1)

Reorder the terms:
4 + C + 5c = 3(-1 + 2c)
4 + C + 5c = (-1 * 3 + 2c * 3)
4 + C + 5c = (-3 + 6c)

Solving
4 + C + 5c = -3 + 6c

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + C + -4 + 5c = -3 + -4 + 6c

Reorder the terms:
4 + -4 + C + 5c = -3 + -4 + 6c

Combine like terms: 4 + -4 = 0
0 + C + 5c = -3 + -4 + 6c
C + 5c = -3 + -4 + 6c

Combine like terms: -3 + -4 = -7
C + 5c = -7 + 6c

Add '-5c' to each side of the equation.
C + 5c + -5c = -7 + 6c + -5c

Combine like terms: 5c + -5c = 0
C + 0 = -7 + 6c + -5c
C = -7 + 6c + -5c

Combine like terms: 6c + -5c = 1c
C = -7 + 1c

Simplifying
C = -7 + 1c

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