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(C+1)=(C)+2C+1
We move all terms to the left:
(C+1)-((C)+2C+1)=0
We add all the numbers together, and all the variables
(C+1)-(3C+1)=0
We get rid of parentheses
C-3C+1-1=0
We add all the numbers together, and all the variables
-2C=0
C=0/-2
C=0
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