C(x)=12x+28

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Solution for C(x)=12x+28 equation: 



(C)=12C+28

We move all terms to the left:

(C)-(12C+28)=0

We get rid of parentheses

C-12C-28=0

We add all the numbers together, and all the variables

-11C-28=0

We move all terms containing C to the left, all other terms to the right

-11C=28

C=28/-11

C=-2+6/11

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