B=8x(2x+10)

Solution for B=8x(2x+10) equation:

=8B(2B+10)

We move all terms to the left:

-(8B(2B+10))=0


We calculate terms in parentheses: -(8B(2B+10)), so:

8B(2B+10)

We multiply parentheses

16B^2+80B

Back to the equation:

-(16B^2+80B)


We get rid of parentheses

-16B^2-80B=0

a = -16; b = -80; c = 0;
Δ = b2-4ac
Δ = -802-4·(-16)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-80}{2*-16}=\frac{0}{-32}
=0
$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+80}{2*-16}=\frac{160}{-32}
=-5
$