B=6/5(j-25)

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Solution for B=6/5(j-25) equation: 



=6/5(B-25)

We move all terms to the left:

-(6/5(B-25))=0



Domain of the equation: 5(B-25))!=0

B∈R



We multiply all the terms by the denominator


-(6=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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