B=4/3(j-49)

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Solution for B=4/3(j-49) equation: 



=4/3(B-49)

We move all terms to the left:

-(4/3(B-49))=0



Domain of the equation: 3(B-49))!=0

B∈R



We multiply all the terms by the denominator


-(4=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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