B=3x(2x+4)

Solution for B=3x(2x+4) equation:

=3B(2B+4)

We move all terms to the left:

-(3B(2B+4))=0


We calculate terms in parentheses: -(3B(2B+4)), so:

3B(2B+4)

We multiply parentheses

6B^2+12B

Back to the equation:

-(6B^2+12B)


We get rid of parentheses

-6B^2-12B=0

a = -6; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-6)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-6}=\frac{0}{-12}
=0
$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-6}=\frac{24}{-12}
=-2
$