B=3/2(j-89)j=

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Solution for B=3/2(j-89)j= equation: 



=3/2(B-89)B=

We move all terms to the left:

-(3/2(B-89)B)=0



Domain of the equation: 2(B-89)B)!=0

B∈R



We multiply all the terms by the denominator


-(3=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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