B=2(3+a)-5

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Solution for B=2(3+a)-5 equation:



=2(3+B)-5
We move all terms to the left:
-(2(3+B)-5)=0
We add all the numbers together, and all the variables
-(2(B+3)-5)=0
We calculate terms in parentheses: -(2(B+3)-5), so:
2(B+3)-5
We multiply parentheses
2B+6-5
We add all the numbers together, and all the variables
2B+1
Back to the equation:
-(2B+1)
We get rid of parentheses
-2B-1=0
We move all terms containing B to the left, all other terms to the right
-2B=1
B=1/-2
B=-1/2

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