B=(7/5)(j-7)

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Solution for B=(7/5)(j-7) equation: 


x in (-oo:+oo)

B = (7/5)*(j-7) // - (7/5)*(j-7)

B-((7/5)*(j-7)) = 0

(-7/5)*(j-7)+B = 0

B-7/5*(j-7) = 0

B-7/5*(j-7) = 0

B-7/5*j+49/5 = 0

B-7/5*j+49/5 = 0

x belongs to the empty set

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