B+3/2(b+45)+(2b-90)+90=540

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Solution for B+3/2(b+45)+(2b-90)+90=540 equation: 



+3/2(B+45)+(2B-90)+90=540

We move all terms to the left:

+3/2(B+45)+(2B-90)+90-(540)=0



Domain of the equation: 2(B+45)!=0

B∈R



We add all the numbers together, and all the variables

3/2(B+45)+(2B-90)-450=0

We get rid of parentheses

3/2(B+45)+2B-90-450=0

We multiply all the terms by the denominator


2B*2(B+45)-90*2(B+45)-450*2(B+45)+3=0

Wy multiply elements

4B^2(B-180B(B-900B(B+3=0

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