B(4-2h)=4(5-3h)

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Solution for B(4-2h)=4(5-3h) equation: 



(4-2B)=4(5-3B)

We move all terms to the left:

(4-2B)-(4(5-3B))=0

We add all the numbers together, and all the variables

(-2B+4)-(4(-3B+5))=0

We get rid of parentheses

-2B-(4(-3B+5))+4=0



We calculate terms in parentheses: -(4(-3B+5)), so:

4(-3B+5)

We multiply parentheses

-12B+20

Back to the equation:

-(-12B+20)



We get rid of parentheses

-2B+12B-20+4=0

We add all the numbers together, and all the variables

10B-16=0

We move all terms containing B to the left, all other terms to the right

10B=16

B=16/10

B=1+3/5

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