B(3t-2)=4(7t-1)

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Solution for B(3t-2)=4(7t-1) equation: 



(3B-2)=4(7B-1)

We move all terms to the left:

(3B-2)-(4(7B-1))=0

We get rid of parentheses

3B-(4(7B-1))-2=0



We calculate terms in parentheses: -(4(7B-1)), so:

4(7B-1)

We multiply parentheses

28B-4

Back to the equation:

-(28B-4)



We get rid of parentheses

3B-28B+4-2=0

We add all the numbers together, and all the variables

-25B+2=0

We move all terms containing B to the left, all other terms to the right

-25B=-2

B=-2/-25

B=2/25

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