B(1)=7,B(n)=B(n-1)-5

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Solution for B(1)=7,B(n)=B(n-1)-5 equation: 



(1)=7.(B)=(B-1)-5

We move all terms to the left:

(1)-(7.(B))=0

We add all the numbers together, and all the variables

-(+7.B)+1=0

We get rid of parentheses

-7.B+1=0

We add all the numbers together, and all the variables

-7B+1=0

We move all terms containing B to the left, all other terms to the right

-7B=-1

B=-1/-7

B=1/7

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