Abs(x)-2abs(x+1)=5

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Solution for Abs(x)-2abs(x+1)=5 equation: 


Simplifying
Abs(x) + -2abs(x + 1) = 5

Multiply bsA * x
bsxA + -2abs(x + 1) = 5

Reorder the terms:
bsxA + -2abs(1 + x) = 5
bsxA + (1 * -2abs + x * -2abs) = 5
bsxA + (-2abs + -2absx) = 5

Reorder the terms:
-2abs + -2absx + bsxA = 5

Solving
-2abs + -2absx + bsxA = 5

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1bsxA' to each side of the equation.
-2abs + -2absx + bsxA + -1bsxA = 5 + -1bsxA

Combine like terms: bsxA + -1bsxA = 0
-2abs + -2absx + 0 = 5 + -1bsxA
-2abs + -2absx = 5 + -1bsxA

Reorder the terms:
-5 + -2abs + -2absx + bsxA = 5 + -1bsxA + -5 + bsxA

Reorder the terms:
-5 + -2abs + -2absx + bsxA = 5 + -5 + -1bsxA + bsxA

Combine like terms: 5 + -5 = 0
-5 + -2abs + -2absx + bsxA = 0 + -1bsxA + bsxA
-5 + -2abs + -2absx + bsxA = -1bsxA + bsxA

Combine like terms: -1bsxA + bsxA = 0
-5 + -2abs + -2absx + bsxA = 0

The solution to this equation could not be determined.

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