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=A2-9A-22
We move all terms to the left:
-(A2-9A-22)=0
We add all the numbers together, and all the variables
-(+A^2-9A-22)=0
We get rid of parentheses
-A^2+9A+22=0
We add all the numbers together, and all the variables
-1A^2+9A+22=0
a = -1; b = 9; c = +22;
Δ = b2-4ac
Δ = 92-4·(-1)·22
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-13}{2*-1}=\frac{-22}{-2} =+11 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+13}{2*-1}=\frac{4}{-2} =-2 $
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