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=A(-1.5A+2.5)
We move all terms to the left:
-(A(-1.5A+2.5))=0
We calculate terms in parentheses: -(A(-1.5A+2.5)), so:We get rid of parentheses
A(-1.5A+2.5)
We multiply parentheses
-1A^2+2.5A
Back to the equation:
-(-1A^2+2.5A)
1A^2-2.5A=0
We add all the numbers together, and all the variables
A^2-2.5A=0
a = 1; b = -2.5; c = 0;
Δ = b2-4ac
Δ = -2.52-4·1·0
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{6.25}}{2*1}=\frac{2.5-\sqrt{6.25}}{2} $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{6.25}}{2*1}=\frac{2.5+\sqrt{6.25}}{2} $
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