A=w(2w-4)

Solution for A=w(2w-4) equation:

=A(2A-4)

We move all terms to the left:

-(A(2A-4))=0


We calculate terms in parentheses: -(A(2A-4)), so:

A(2A-4)

We multiply parentheses

2A^2-4A

Back to the equation:

-(2A^2-4A)


We get rid of parentheses

-2A^2+4A=0

a = -2; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-2)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-2}=\frac{-8}{-4}
=+2
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-2}=\frac{0}{-4}
=0
$