A=a+2(b+c)/3

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Solution for A=a+2(b+c)/3 equation: 


x in (-oo:+oo)

A = (2*(b+c))/3+a // - (2*(b+c))/3+a

A-((2*(b+c))/3)-a = 0

(-2/3)*(b+c)+A-a = 0

A-2/3*(b+c)-a = 0

A-2/3*(b+c)-a = 0

A-a-2/3*b-2/3*c = 0

A-a-2/3*b-2/3*c = 0

x belongs to the empty set

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