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=6A(2A+6)
We move all terms to the left:
-(6A(2A+6))=0
We calculate terms in parentheses: -(6A(2A+6)), so:We get rid of parentheses
6A(2A+6)
We multiply parentheses
12A^2+36A
Back to the equation:
-(12A^2+36A)
-12A^2-36A=0
a = -12; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·(-12)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*-12}=\frac{0}{-24} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*-12}=\frac{72}{-24} =-3 $
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