A=5/2(b-20)

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Solution for A=5/2(b-20) equation: 


x in (-oo:+oo)

A = (5/2)*(b-20) // - (5/2)*(b-20)

A-((5/2)*(b-20)) = 0

(-5/2)*(b-20)+A = 0

A-5/2*(b-20) = 0

A-5/2*(b-20) = 0

A-5/2*b+50 = 0

A-5/2*b+50 = 0

x belongs to the empty set

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